Question

Consider the following one-sided limit.\\ $\lim_{h \to 13^+} \left(\frac{h^2 + 169}{h - 13}\right)$\\ Step 1 of 2: Approximate the limit by filling in the table. Round to the nearest thousandth.\\ Answer\\ $\begin{array}{|c|c|} \hline h & y \\ \hline 14 & \\ \hline 13.1 & \\ \hline 13.01 & \\ \hline 13.001 & \\ \hline \end{array}$

          Consider the following one-sided limit.\\
$\lim_{h \to 13^+} \left(\frac{h^2 + 169}{h - 13}\right)$\\
Step 1 of 2: Approximate the limit by filling in the table. Round to the nearest thousandth.\\
Answer\\
$\begin{array}{|c|c|}
\hline
h & y \\
\hline
14 & \\
\hline
13.1 & \\
\hline
13.01 & \\
\hline
13.001 & \\
\hline
\end{array}$

Consider the following one-sided limit.

limh → 13^+((h^2 + 169)/(h - 13))

Step 1 of 2: Approximate the limit by filling in the table. Round to the nearest thousandth.

Answer

h y

14

13.1

13.01

13.001

Added by Joaquin B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

05/23/2022

Step 1

h | (h^2 + 169)/(h - 13) ----------------------------------- 14 | (14^2 + 169)/(14 - 13) = (196 + 169)/1 = 365 13.1 | (13.1^2 + 169)/(13.1 - 13) = (171.61 + 169)/0.1 = 340.1 13.01 | (13.01^2 + 169)/(13.01 - 13) = (169.2601 + 169)/0.01 = Show more…

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Consider the following one-sided limit. lim_(h->13^(+))((h^(2)+169)/(h-13)) Step 1 of 2 : Approximate the limit by filling in the table. Round to the nearest thousandth. Answer Consider the following one-sided limit h2+169 lim h13+ h - 13 Step 1 of 2 : Approximate the limit by filling in the table. Round to the nearest thousandth. Answer h y 14 13.1 13.01 13.001