00:01
In this question, we are going to use investigation and a quadratic model to maximize the area of a rectangular field.
00:11
We've got a river and fencing.
00:18
We know the total length of fencing.
00:21
So let's say each dimension here is x.
00:25
The total length of fencing is 3200, and i would take away the two xes that are folded from the fencing.
00:37
To make the sides.
00:41
So a couple of examples we might have.
00:44
Let's say x is 200.
00:52
If x is 200, the other dimension is 3200 minus 400 or 2 ,800.
01:00
That area length times width is 560 ,000.
01:11
What if the x value is 400, 3200 minus 800 is 2 ,400, and then the area length times width is 960 ,000, so it's grown.
01:37
What about, we'll do one more investigation.
01:41
What about 600, 3200 minus 1 ,200 is 2 ,000, and then the area that rectangle is 1 ,200 ,000...