Consider the following reaction . MgCl 2 (aq)+2 NaOH(aq) longrightarrow Mg(OH) 2 (s)+2 NaCl(aq) A 167.0 mL solution of 0.296 M MgCl 2 reacts with a 39.66 mL solution of 0.587 M NaOH to produce Mg(OH) 2 and NaCl.
Added by Melissa G.
Step 1
To do this, use the concentration and volume of the MgCl2 solution. The formula to calculate moles is: moles = concentration (M) × volume (L). For MgCl2, the concentration is 0.296 M and the volume is 167.0 mL (which needs to be converted to liters by dividing by Show more…
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