00:01
Hello everyone in this question we have been given a segment of the gene that has this sequence.
00:10
First of all we need to make an mrnh sequence out of this dna segment that will be complemented to this sequence.
00:20
D forms two hydrogen bonds with adenine, that is, complemented to adenine.
00:26
A is complemented to thiamine but here we are talking about.
00:29
M rna so instead of thyme and uracine will be present.
00:35
Cytocin is complementary to guanthymine to adenine guanin to cytoin then again guanin to cytosin then a to u t to a to u c to g c u u u u uaa c to g c u u u u a c and we know that a codon consists of three bases.
01:05
So this aug will code for methionine in case of eukaryotes and formal methamin in procarriots as this aug is basically a start codon.
01:21
Then the acc codes for thryonin.
01:25
The uau codes for thyrin.
01:27
The uau codes for tyrosin and the g -c.
01:31
Codes for alanine where u a a code for a stop codon so the translation will stop here and the polypeptide chain achieved is methionine threonein tyrosine and alanine these are the one letter code for the amino acids that have been synthesized here then we have been said that insert a see between the t and the second a in the third codon...