Consider the following series. \sum_{n=1}^{\infty} \frac{n^{k-1}}{n^k+3} \quad k>2 Use the Limit Comparison Test to complete the limit. \lim_{n \to \infty} \frac{n^{k-1}}{n^k+3} \quad \to L>0 Determine the convergence or divergence of the series. \circ converges \circ diverges Need Help? Read It Watch It Master It 8. [0.5/1 Points] DETAILS PREVIOUS ANSWERS LARCALC12 9.4.026. Consider the following series. \sum_{n=1}^{\infty} \sin(\frac{1}{n}) Use the Limit Comparison Test to complete the limit. \lim_{n \to \infty} \frac{\sin(\frac{1}{n})}{\frac{1}{n}} \quad \to L>0 Determine the convergence or divergence of the series. \circ converges \circ diverges Need Help? Read It Watch It
Added by Chase M.
Close
Your feedback will help us improve your experience
Likhit Ganedi and 94 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the Limit Comparison Test to determine the convergence or divergence of the series: lim =L> 0 converges diverges
Likhit G.
Use the limit comparison test to determine whether the series converges or diverges. $$ \sum_{n=1}^{\infty} \frac{8 n^{2}-7}{e^{n}(n+1)^{2}} $$
Infinite Series
Positive-Term Series
Use the Limit Comparison Test to determine the convergence or divergence of the series ∑_{n=0}^{∑} 1/∑(n^2+1) lim_{n→∑} (1/∑(n^2+1)) / │ │ = L > 0 converges diverges
Sam S.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD