Consider the following thermochemical equation: CaCO3(s) CaO(s) + CO2 Ho = +178 kJ a) How many moles of CaCO3 are in 28.5g of CaCO3? moles b) How much heat must be absorbed by 28.5 g of CaCO3 to convert it completely to CaO? kJ
Added by Jason S.
Step 1
5g of CaCO3. Given: Mass of CaCO3 = 28.5g Molar mass of CaCO3 = 40.08g/mol + 12.01g/mol + 3(16.00g/mol) = 100.09g/mol Number of moles = Mass / Molar mass Number of moles = 28.5g / 100.09g/mol Number of moles ≈ 0.2847 moles ** Show more…
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