The following thermochemical equation is for the reaction of calcium carbonate(s) to form calcium oxide and carbon dioxide(g). CaCO3(s)---> CaO(s) + CO2(g) H = 178 kJ How many grams of CaCO3(s) would react if 52.3 kJ of energy were provided? =____grams
Added by Richard B.
Step 1
Given: ΔH = 178 kJ, energy provided = 52.3 kJ Number of moles of CaCO3 = energy provided / ΔH Number of moles of CaCO3 = 52.3 kJ / 178 kJ/mol Number of moles of CaCO3 = 0.294 moles Show more…
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The following thermochemical equation is for the reaction of calcium carbonate(s) to form calcium oxide and carbon dioxide(g). CaCO3(s) CaO(s) + CO2(g) H = 178 kJ How many grams of CaCO3(s) would be made to react if 63.0 kJ of energy were provided? grams
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