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Hi there.
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In this question, we are given this unbalanced equation.
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I did leave out the states of matter because they are not important for what we are trying to do in this question.
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But the first thing that we do need to do is balance this equation.
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So i see hydrogen in most of these compounds.
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So i'm saving hydrogen for last.
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But let's look at the acetate.
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On the reactant side, there's one acetate ion.
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On the product side, there are two.
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So i'm going to add a two.
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In front of the acetic acid on the reactant side.
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There's one calcium and one calcium.
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Now let's look at our hydrogens and oxygens.
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On the reactant side, there are four hydrogen and two oxygen.
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On the product side, we have a water molecule.
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If i put a two in front of there, we will have four hydrogen and two oxygen...