Consider the following. x = t - 2 sin(t), y = 1 - 2 cos(t), 0 le t le 8pi Set up an integral that represents the length of the curve. $int_0^{8pi} left( sqrt{9 - 8 cos(t)} ight) dt$ \ Use your calculator to find the length correct to four decimal places.
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We are given parametric equations for x and y in terms of t: x = t - 2 sin(t) and y = 1 - 2 cos(t). Show more…
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