Consider the function $f(x) = \sin(2 - 3x)$ between $x = 0$ and $x = \frac{\pi}{2}$. For which values of $x$ in this interval does the graph of $y = f(x)$ have an inflection point?\nSelect one:\nAt both $x = 0$ and $x = \frac{2}{3}$.\nOnly at $x = \frac{2}{3}$.\nAt and $x = \frac{2}{3} + \frac{\pi}{6}$ and $x = \frac{2}{3} - \frac{\pi}{6}$.\nAt only $x = \frac{6}{5}$.
Added by Cheryl S.
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The first derivative of f(x) is f'(x) = -3cos(2-3x). The second derivative of f(x) is f''(x) = 9sin(2-3x). Show more…
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