Question

15. Consider the function $f(x) = 2x^3 - 3x^2 - 36x$. a) What is the maximum number of local extrema this function can have? Explain. b) What is the maximum number of points of inflection this function can have? c) Find and classify the critical points. Identify the intervals of increase and decrease, and state the intervals of concavity. d) Sketch the function.

          15. Consider the function $f(x) = 2x^3 - 3x^2 - 36x$.
a) What is the maximum number of local extrema this function can have? Explain.
b) What is the maximum number of points of inflection this function can have?
c) Find and classify the critical points. Identify the intervals of increase and decrease, and state
the intervals of concavity.
d) Sketch the function.
        
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15. Consider the function f(x) = 2x^3 - 3x^2 - 36x.
a) What is the maximum number of local extrema this function can have? Explain.
b) What is the maximum number of points of inflection this function can have?
c) Find and classify the critical points. Identify the intervals of increase and decrease, and state
the intervals of concavity.
d) Sketch the function.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Consider the function f(x)=2x^(3)-3x^(2)-36x. a) What is the maximum number of local extrema this function can have? Explain. b) What is the maximum number of points of inflection this function can have? c) Find and classify the critical points. Identify the intervals of increase and decrease, and state the intervals of concavity. d) Sketch the function. 15. Consider the function f(x) = 2x3 - 3x2 36x a) What is the maximum number of local extrema this function can have? Explain b) What is the maximum number of points of inflection this function can have? c) Find and classify the critical points. Identify the intervals of increase and decrease, and state the intervals of concavity. d) Sketch the function
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Transcript

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00:02 Okay, so we're given the function y is equal to x cubed over 3 plus x squared over 2 minus 2x plus 1.
00:13 Let's first calculate y prime.
00:15 This is just, well the 3 comes out, so this just can be x squared plus x minus 2.
00:22 Okay, and the critical points are where y prime is equal to 0, so we have to set x squared plus x minus 2 is equal to 0, which you can do by factoring.
00:39 So note that you can factor this as x plus 2 times x minus 1.
00:49 Okay, so this means that the critical points are x equals minus 2 and x equals 1 are the critical points.
01:11 Okay, so now we can find where it's increasing or decreasing by making a sine chart...
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