Consider the function $f(x) = 3 \tan(x)$. \\ Find the equation of the line normal (perpendicular) to the curve $f(x) = 3 \tan(x)$ at the point where $x = -\frac{\pi}{6}$. \\ Your response should be in the form $y = m \cdot x + b$ omitting the $y=$ part and the values should be rounded to 3 significant digits.
Added by Shawn F.
Close
Step 1
The derivative of tan(x) is sec^2(x), so the derivative of f(x)=3tan(x) is f'(x)=3sec^2(x). Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 78 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
1. Find the slope of the tangent line to the graph of the function y = f(x) = 3.5x^2 at point x = 6. Your answer should be precise to the third decimal. Answer: 42 2. Find the equation of this tangent line. You may want to use your answer from part 1. Answer: y =
Sri K.
Find the equation of the line normal to the curve of y = 3 tan x^2 at x = 0.25
Shima S.
Find the lines that are (a) tangent and (b) normal to the curve at the given point. $$6 x^{2}+3 x y+2 y^{2}+17 y-6=0, \quad(-1,0)$$
More Derivatives
Implicit Differentiation
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD