Question

Consider the function f(x)=3x^(2)+ 2x-1. We want to find the slope of the tangent at the point (2,f(2)).

Name: consider the function fx3x2 2x 1 we want to find the slope of the tangent at the point 2f2 91095
Uploaded: 2023-09-05T06:29:21-08:00
Duration: 2 min 36 s
Channel: Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkouxdh4Ofnmgpwkor7Leaonfpu0Ubfpua Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkokttmmj7Lscvwvlptp4Rlhbswcdg9.Wy
Description: consider the function fx3x2 2x 1 we want to find the slope of the tangent at the point 2f2 91095

          Consider the function f(x)=3x^(2)+ 2x-1. We want to find the slope of the tangent at the point (2,f(2)).

Added by Asunci-N B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkouxdh4Ofnmgpwkor7Leaonfpu0Ubfpua Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkokttmmj7Lscvwvlptp4Rlhbswcdg9.Wy

09/05/2023

Step 1

The power rule states that if we have a function of the form f(x) = ax^n, then the derivative is given by f'(x) = nax^(n-1). Applying the power rule to the function f(x) = 3x^2 + 2x - 1, we get: f'(x) = 2(3)x^(2-1) + 1(2)x^(1-1) + 0 = 6x + 2 Show more…

Show all steps

Thanks for your feedback!

Consider the function f(x)=3x^(2)+ 2x-1. We want to find the slope of the tangent at the point (2,f(2)).

Play audio

Feedback

Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkouxdh4Ofnmgpwkor7Leaonfpu0Ubfpua Bcrypt_Sha256$$2B$12$We1Wwocamog01O5I.V2Tkokttmmj7Lscvwvlptp4Rlhbswcdg9.Wy and 95 other subject Calculus 1 / AB educators are ready to help you.