Consider the function $h(x)$, for which $h(2) = 7$ and $h'(2) = -2$. Find $f'(2)$ for the function $f(x) = \frac{h(x)}{x}$. f'(2) = Given that: f(1) = 5, f'(1) = 3, g(1) = 3, g'(1) = 9, calculate the following: $(fg)'(1) = $ $(f/g)'(1) = $ $(g/f)'(1) =
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Since f(1) = 5 and f(1) = 3, we can use the definition of the derivative to find f'(x): f'(x) = (f(x) - f(1))/(x - 1) Plugging in x = 2, we have: f'(2) = (f(2) - f(1))/(2 - 1) = (7 - 5)/(2 - 1) = 2/1 = 2 So, f'(2) = 2. Show more…
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