Question

Consider the integral, \begin{equation} \int_0^{33} 10(x - 1)^{-1/5} dx \end{equation} If the integral converges, evaluate it. Otherwise, if the integral is divergent, enter $\infty$ or $-\infty$ if it diverges towards positive or negative infinity, respectively, or type an upper-case D if it diverges without being $\pm\infty$.

          Consider the integral, \begin{equation*}
\int_0^{33} 10(x - 1)^{-1/5} dx
\end{equation*} If the integral converges, evaluate it. Otherwise, if the integral is divergent, enter $\infty$ or $-\infty$ if it diverges towards positive or negative infinity, respectively, or type an upper-case D if it diverges without being $\pm\infty$.

Consider the integral,
∫0^33 10(x - 1)^-1/5 dx
If the integral converges, evaluate it. Otherwise, if the integral is divergent, enter ∞ or -∞ if it diverges towards positive or negative infinity, respectively, or type an upper-case D if it diverges without being ±∞.

Added by Danielle B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

10/29/2022

Step 1

The given integral is: \int_0^3 10(x-1)^{-(1/5)}dx We can see that the integrand has a singularity at x = 1, which is within the interval of integration. To check for convergence, we can split the integral into two parts: \int_0^3 10(x-1)^{-(1/5)}dx = \int_0^1 Show more…

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Consider the integral, int_0^33 10(x-1)^{-(1/5)}dx. If the integral converges, evaluate it. Otherwise, if the integral is divergent, enter infty or -infty if it diverges towards positive or negative infinity, respectively, or type an upper-case D if it diverges without being +-infty. Answer: ◻ Submit answer Next item Consider the integral, int_0^1 10(x-1)^{-1/5}dx. If the integral converges, evaluate it. Otherwise, if the integral is divergent, enter infty or -infty if it diverges towards positive or negative infinity, respectively, or type an upper-case D if it diverges without being +-infty. Answer: Submit answer Next item