00:01
Hello everyone, in this problem we are given with the lines l1 and l2 where a is a constant.
00:07
So here we are also given that the lines l1 and l2 intersect at the point p.
00:18
So in the first part we need to find the value of a here.
00:23
So from the l1 line we can have the x plus 3 by 1 to be equal to y plus 2 by 4 to be equal to z minus a divided by 2 which is equal to t.
00:40
And from this l2 we can have the equation as x minus 6 divided by minus 3 to be equal to y minus 2 divided by 4 to be equal to z minus 1 divided by minus 1 to be equal to s.
00:58
So here we are given that the lines l1 and l2 intersect at the p.
01:03
So we can equate the corresponding x, y and z coordinates individually.
01:09
So we get minus 3 plus t to be equal to 6 minus 3, yes.
01:19
Let us take this to be first equation.
01:23
This is for x equating the x coordinates and for equating y coordinates we can have minus 2 plus 4t to be equal to 2 plus 4s.
01:34
Let us take this to be equation number 2.
01:36
So now solving these two equations we can have the value of s to be 2 and t to be 3.
01:44
So now equating the z coordinates here so we have a plus 2t to be equal to 1 minus s...