Question

1. Consider the Markov chain whose transition probability matrix is given by (a) Starting in state 2, determine the probability that the process is absorbed into state 0. (b) Starting in state 0, determine the mean time that the process spends in state 0 prior to absorption and the mean time that prior to absorption. P = egin{bmatrix} 0.2 & 0.3 & 0 & 0.5 \ 1 & 0 & 0 & 0 \ 0.2 & 0 & 0.6 & 0.2 \ 0 & 0 & 0 & 1 end{bmatrix}

          1. Consider the Markov chain whose transition probability matrix is given by
(a) Starting in state 2, determine the probability that the process is absorbed into state 0.
(b) Starting in state 0, determine the mean time that the process spends in state 0 prior to absorption and the mean time that prior to absorption.
P = egin{bmatrix} 0.2 & 0.3 & 0 & 0.5 \ 1 & 0 & 0 & 0 \ 0.2 & 0 & 0.6 & 0.2 \ 0 & 0 & 0 & 1 end{bmatrix}
        
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1. Consider the Markov chain whose transition probability matrix is given by
(a) Starting in state 2, determine the probability that the process is absorbed into state 0.
(b) Starting in state 0, determine the mean time that the process spends in state 0 prior to absorption and the mean time that prior to absorption.
P = eginbmatrix 0.2     0.3     0     0.5  1     0     0     0  0.2     0     0.6     0.2  0     0     0     1 endbmatrix

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Consider the Markov chain whose transition probability matrix is given by (a) Starting in state 2, determine the probability that the process is absorbed into state 0. (b) Starting in state 0, determine the mean time that the process spends in state 0 prior to absorption and the mean time that prior to absorption.
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Transcript

-
00:01 In this question, we have been given the markov chain.
00:03 Post -transition probability matrix is given as matrix p.
00:06 In the first part, we need to start in stage two, determine the probability that the process is absorbed in state zero.
00:15 So probability that the process is absorbed in state zero.
00:27 So that is what we have to find, correct? so we can one thing observe that each column, sorry, each row if you consider, the sum of each row.
00:43 So since sum of each row, if you observe, it is going to be equal to one only, or the first up till fourth row.
00:56 So this is going to be equal to one.
00:57 So what does this imply? then this will imply that the same matrix p will be representing the required probability...
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