00:06
Hello, in this question, we have been given an isotope of silver, which is ag 47107.
00:18
Okay, and we have to determine what is the number of electrons, protons and neutrons in this one.
00:24
Okay, so the number of proton is equal to the atomic number, so it will be 47.
00:28
Now, number of electrons is also equal to the proton number, which will be 47.
00:32
Number of neutrons is equal to mass number minus the proton number, which is also equal to the atomic number.
00:40
So this one will be 107 minus 47.
00:43
So it will be 60.
00:47
Okay, so this is the a part.
00:50
Now next is the symbol for another isotope of silver with 62 neutrons.
00:59
Okay, so what we do is, so this one is 62 neutrons.
01:06
So what will happen is the number of the mass number will change, right? so we write it like this.
01:12
So ag, see the atomic number will remain same.
01:16
But the mass number will change, right? so it will be 47 plus 62, right? so that will be ag 47 and then 109.
01:36
Because 47 plus 62 is 109.
01:39
Okay, because mass number is equal to number of protons plus number of neutrons.
01:43
Proton number remains same, but the number of neutrons has changed here.
01:46
So it will be 62 plus 47.
01:48
So it will be 109...