00:01
In this question we are given that this is the beam having a length of 6 meter and this loading is triangular and the peak value is 5 .6 newton per meter is it newton or kilometer? kilo, this is the loading.
00:21
Now here this would be reaction, this would be reaction like this.
00:26
These are the reaction coaches.
00:29
H a let us say v a nv v.
00:35
A.
00:35
All right.
00:36
So now sigma m .a must be 0.
00:43
Sigma m .a must be equal to 0.
00:46
Right.
00:47
If sigma m .a is 0, then 5 .6 half into 5 .6 into 6.
00:55
Multiply at what will be the point of application? 2 l by 3? that means sorry, l by 3.
01:03
L by 3.
01:03
L by 3 would be the point of application.
01:04
So 2 meters.
01:05
Minus vb into 6.
01:08
That would be 0.
01:10
So from here we can clearly see that vb would be equal to 6 .6 cancels out 2 % percent of svp.
01:17
Would be 5 .6 kilo noda...