00:01
So given the equation as x equal to 4 plus 2 cosine t and y equal to 6 plus 2 sine t.
00:13
We write this to solve for our trig values.
00:17
We're going to have x minus 4 divided by 2 to equal cosine t and y minus 6 divided by 2 to equal sine t.
00:29
So then using the equation cosine squared t plus sine squared t equal to 1, that's going to give us x minus 4 over 2 squared plus y minus 6 over 2 squared equal to, in this case, one squared.
01:05
No, i'm sorry, two squared.
01:06
So in this case, our h is going to be equivalent to 4.
01:19
Our k is going to be equivalent to 6.
01:25
And our r is going to be equivalent to 2.
01:31
So the initial point has a coordinates of, so initial points are when our trig functions are equal to zero.
01:43
So this is going to be at, this is when t is pi over 2.
01:52
So when t is pi over 2, that's going to be cosine of t equal to zero.
02:02
So in this case, solving for x minus 4 over 2 equal to zero.
02:12
Then we're going to have x minus 4 equal to zero.
02:17
So x has to be 4...