00:01
Hi, from the question given that consider the given power series sum of n is equal to 1 to infinity minus 6 to the power of n divided by square root of n times of x plus 8 the whole power n.
00:15
So here we need to find the radius of convergence and the interval of convergence.
00:20
So here let a n is equal to minus 6 to the power of n x plus 8 to the power of n divided by under root of n.
00:28
So here a n plus 1 is equal to minus 6 to the power of n plus 1 times x plus 8 to the power of n plus 1 divided by square root of n plus 1.
00:41
So now limit x tends to infinity a n plus 1 divided by a n this is not x this is n tends to infinity.
00:58
So that is equal to limit n tends to infinity a n plus 1 is minus 6 to the power of n plus 1 times of x plus 8 to the power of n plus 1 divided by square root of n plus 1 multiplied with square root of n divided by minus 6 to the power of n x plus 8 to the power of n.
01:21
So for further simplification we obtain limit n tends to infinity 6 times of x plus 8 divided by 1 times of square root of n divided by square root of n plus 1.
01:39
So for further simplification we obtain absolute value of 6 plus 6 times of x plus 8 times of 1.
01:50
So that is equal to 6 times of x plus 8 under the absolute value.
01:55
So the series is converges series is converges if absolute value of 6 times of x plus 8 is less than 1...