Question

Consider the production of flower color in the Japanese morning glory (Pharbitis nil). Dominant alleles of either of two separate genes $(A /-\cdot b / b \text { or } a / a \cdot B /-)$ produce purple petals. $A /-\cdot B /-$ produces blue petals, and $a / a \cdot b / b$ produces scarlet petals. Deduce the genotypes of parents and progeny in the following crosses: $$\begin{array}{cll} \text { Cross } & \text { Parents } & \text { Progeny } \\ \hline 1 & \text { blue } \times \text { scarlet } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple : } \frac{1}{4} \text { scarlet } \\ 2 & \text { purple } \times \text { purple } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple }: \frac{1}{4} \text { scarlet } \\ 3 & \text { blue } \times \text { blue } & \frac{3}{4} \text { blue }: \frac{1}{4} \text { purple } \\ 4 & \text { blue } \times \text { purple } & \frac{3}{8} \text { blue }: \frac{4}{8} \text { purple }: \frac{1}{8} \text { scarlet } \\ 5 & \text { purple } \times \text { scarlet } & \frac{1}{2} \text { purple }: \frac{1}{2} \text { scarlet } \\ \hline \end{array}$$

          Consider the production of flower color in the Japanese morning glory (Pharbitis nil). Dominant alleles of either of two separate genes $(A /-\cdot b / b \text { or } a / a \cdot B /-)$ produce purple petals. $A /-\cdot B /-$ produces blue petals, and $a / a \cdot b / b$ produces scarlet petals. Deduce the genotypes of parents and progeny in the following crosses:
$$\begin{array}{cll}
\text { Cross } & \text { Parents } & \text { Progeny } \\
\hline 1 & \text { blue } \times \text { scarlet } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple : } \frac{1}{4} \text { scarlet } \\
2 & \text { purple } \times \text { purple } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple }: \frac{1}{4} \text { scarlet } \\
3 & \text { blue } \times \text { blue } & \frac{3}{4} \text { blue }: \frac{1}{4} \text { purple } \\
4 & \text { blue } \times \text { purple } & \frac{3}{8} \text { blue }: \frac{4}{8} \text { purple }: \frac{1}{8} \text { scarlet } \\
5 & \text { purple } \times \text { scarlet } & \frac{1}{2} \text { purple }: \frac{1}{2} \text { scarlet } \\
\hline
\end{array}$$

Added by Logan C.

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