Consider the reaction at equilibrium:
4NH3(g) + 5O2(g) ⇌ 4NO(g) + 6H2O(g); ΔH = -904.4 kJ.
The concentration of NO at equilibrium will increase as:
- the volume of the container in which the reaction occurs decreases
- [H2O] increases
- [O2] decreases
- [NH3] increases.