Question

Consider the reaction of phosphorus with water and iodine. 2P (s) + 6H2O (l) + 3I2 (s) → 6HI (aq) + 2H3PO3 (aq). Determine the limiting reactant in a mixture containing 120 g of P, 187 g of H2O, and 1.65×10^3 g of I2. Calculate the maximum mass (in grams) of hydroiodic acid, HI, that can be produced in the reaction.

Name: consider the reaction of phosphorus with water and iodine 2p s 6h2o l 3i2 s 6hi aq 2h3po3 aq determine the limiting reactant in a mixture containing 120 g of p 187 g of h2o and 165103 g of i 84342
Uploaded: 2022-08-04T15:25:46-08:00
Duration: 3 min 12 s
Channel: Brooke Smith
Description: consider the reaction of phosphorus with water and iodine 2p s 6h2o l 3i2 s 6hi aq 2h3po3 aq determine the limiting reactant in a mixture containing 120 g of p 187 g of h2o and 165103 g of i 84342

          Consider the reaction of phosphorus with water and iodine. 2P (s) + 6H2O (l) + 3I2 (s) → 6HI (aq) + 2H3PO3 (aq). Determine the limiting reactant in a mixture containing 120 g of P, 187 g of H2O, and 1.65×10^3 g of I2. Calculate the maximum mass (in grams) of hydroiodic acid, HI, that can be produced in the reaction.

Added by Raquel M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Brooke Smith

08/04/2022

Step 1

Given: - 120 g of P - 187 g of H2O - 1.65×10^3 g of I2 Molar masses: - P: 30.97 g/mol - H2O: 18.02 g/mol - I2: 253.81 g/mol Moles of P = 120 g / 30.97 g/mol = 3.87 mol Moles of H2O = 187 g / 18.02 g/mol = 10.38 mol Moles of I2 = 1.65×10^3 g / 253.81 g/mol = 6.50 Show more…

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Consider the reaction of phosphorus with water and iodine. 2P (s) + 6H2O (l) + 3I2 (s) → 6HI (aq) + 2H3PO3 (aq). Determine the limiting reactant in a mixture containing 120 g of P, 187 g of H2O, and 1.65×10^3 g of I2. Calculate the maximum mass (in grams) of hydroiodic acid, HI, that can be produced in the reaction.