00:01
Solution for this question is to find all keys of the relation r, we can use the closer of attributes method starting with the a, b.
00:23
So we can find the closer to the a, b as a, b, c, d.
00:32
Since the a, b is a candidate key we have found one key.
00:38
So we can also check the closer of the a, c, a, d, a, e, b, c, b, d, b, e, c, d, c, e and d, e.
01:01
None of them result in all attributes of the r.
01:05
So a, b it is the only key then b, r is not in the vcnf because there is non trivial frequency dependency which is c to d where c is not the super key...