Question

Consider the system shown in Fig. P6.81. The rope and pulley have negligible mass, and the pulley is frictionless. Initially the $6.00 \mathrm{~kg}$ block is moving downward and the $8.00 \mathrm{~kg}$ block is moving to the right, both with a speed of $0.900 \mathrm{~m} / \mathrm{s}$. The blocks come to rest after moving $2.00 \mathrm{~m}$. Use the work energy theorem to calculate the coefficient of kinetic friction between the $8.00 \mathrm{~kg}$ block and the tabletop.

Name: Consider the system shown in Fig. P6.81. The rope and pulley have negligible mass, and the pulley is frictionless. Initially the 6.00 kg block is moving downward and the 8.00 kg block is moving to the right, both with a speed of 0.900 m / s. The blocks come to rest after moving 2.00 m. Use the work energy theorem to calculate the coefficient of kinetic friction between the 8.00 kg block and the tabletop.
Uploaded: 2022-12-04T18:46:51-08:00
Duration: 3 min 42 s
Channel: Ivan Kochetkov

          Consider the system shown in Fig. P6.81. The rope and pulley have negligible mass, and the pulley is frictionless. Initially the $6.00 \mathrm{~kg}$ block is moving downward and the $8.00 \mathrm{~kg}$ block is moving to the right, both with a speed of $0.900 \mathrm{~m} / \mathrm{s}$. The blocks come to rest after moving $2.00 \mathrm{~m}$. Use the work energy theorem to calculate the coefficient of kinetic friction between the $8.00 \mathrm{~kg}$ block and the tabletop.

Added by Ricky M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

12/04/2022

Step 1

Step 1:** Apply the work-energy theorem to the system: Initial kinetic energy + Work done by friction = Final kinetic energy + Final potential energy ** Show more…

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Consider the system shown in Fig. P6.81. The rope and pulley have negligible mass, and the pulley is frictionless. Initially the $6.00 \mathrm{~kg}$ block is moving downward and the $8.00 \mathrm{~kg}$ block is moving to the right, both with a speed of $0.900 \mathrm{~m} / \mathrm{s}$. The blocks come to rest after moving $2.00 \mathrm{~m}$. Use the work energy theorem to calculate the coefficient of kinetic friction between the $8.00 \mathrm{~kg}$ block and the tabletop.