00:01
In this problem, we have to calculate the coefficient of kinetic friction mu between the block a and the table top.
00:08
So, suppose coefficient of kinetic friction is mu, then the direction of friction force will be in this direction.
00:16
This is friction force.
00:18
And we know that this is normal force which will act in the upper direction and in the downward direction.
00:24
Weight will act in the downward direction.
00:27
And here suppose this tension is t in the string, right? and if we see block b as weight 3 .2 newton, so this will act in the downward direction and tension will be same, which is t.
00:45
So it is given that this system, or we can say it descends, block b descends at a constant speed, that means acceleration will be zero.
00:56
So we can say this tension force will be equal to weight of block b that is equals to 3 .2 newton.
01:06
Now if we see on block a it is also moving with constant speed...