Now, let's find b3, b4, b5, and b6.
b3 = 2b2 + b1 - 2b0 = 2(3) + 2 - 2(0) = 6 + 2 = 8
b4 = 2b3 + b2 - 2b1 = 2(8) + 3 - 2(2) = 16 + 3 - 4 = 15
b5 = 2b4 + b3 - 2b2 = 2(15) + 8 - 2(3) = 30 + 8 - 6 = 32
b6 = 2b5 + b4 - 2b3 = 2(32) + 15 - 2(8) = 64 + 15 - 16 = 63
So,
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