00:05
So we have v1 is 112, v2 is 101, and v3 is 213.
00:14
So these are the three vectors given.
00:19
We need to check whether these are linearly independent.
00:22
So it's enough to find the determinant of this.
00:25
Keep all the vectors in a row form 112, 101, 213.
00:31
So let's find the determinant.
00:34
So we can use the properties of determinants, so 112.
00:37
Subract second row minus first row.
00:39
So it is 0, negative 1 ,000.
00:41
Negative 1, subtract third row, third row is third row minus two times the first row.
00:49
So it's 0 minus 1 minus 1.
00:53
You can see the two rows are identical, so the determinant is 0.
00:58
So that means the vectors are linearly dependent.
01:01
So v1, v2, v3 are linearly dependent, linearly dependent because the determinant is 0.
01:10
Now, the next question is, the span of v1, v2, v3 is r cubed.
01:16
Now i can ignore v3 because v3 is actually depending on v1 and v2.
01:21
And v1 in v2 are obviously linearly independent because two non -parallel vectors are obviously linearly independent.
01:27
Now the question, second question we can frame it as does v1 and v2 no need of v3? does i mean, does span of v1 and v2 can it give rq? let's see.
01:44
What do you mean by span of v1 and v2? lambda into 112 plus some mu into 101...