Consider the equation \ln(x - 1) + \cos(x - 1) = 0. Find an approximation of it's root in [1, 2] to an absolute error less than $10^{-12}$ with one of the methods covered in class.
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In this case, the equation is ln(x-1) + cos(x-1) = 0. Let's evaluate the equation at the endpoints of the interval [1, 2]: At x = 1: ln(1-1) + cos(1-1) = ln(0) + cos(0) = -∞ + 1 = -∞ At x = 2: ln(2-1) + cos(2-1) = ln(1) + cos(1) = 0 + 0.5403 = 0.5403 Since the Show more…
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