1. Consider three point charges located at the corners of a...

Name: 1. Consider three point charges located at the corners of a right triangle as shown in Fig., where q1=q3 = 5.00 ??, q2 = -2?C, and a= 0.100m. Find the resultant force exerted on q3.
Uploaded: 2022-04-03T09:45:22-08:00
Duration: 6 min 1 s
Channel: Darshan Maheshwari
Description: 1. Consider three point charges located at the corners of a right triangle as shown in Fig., where q1=q3 = 5.00 ??, q2 = -2?C, and a= 0.100m. Find the resultant force exerted on q3.

1. Consider three point charges located at the corners of a right triangle as shown in Fig., where q1=q3 = 5.00 ??, q2 = -2?C, and a= 0.100m. Find the resultant force exerted on q3.

Transcript

00:01 Consider the three point charges located at the corners of the right triangle where q1 and q3 are equal and q2 is negative.

00:07 So we're here.

00:08 So what is the result in force acting on q3? so at q3, one of the forces is definitely attractive like this and one of the forces repulsive in nature.

00:17 And let's say this angle is theta.

00:20 So this angle is also theta because they are vertically opposite angles.

00:24 So you've got to make the components of this force.

00:26 So let's say this is f, let me call this f1.

00:30 And let me call this as f2.

00:33 So it will be f1 cosine of theta and the vertical component will be f1 sign of teta.

00:39 So what will be the net force? i think the force towards the x, x axis, that's going to be f1, cosine of theta minus f2.

00:55 What is f1? f1 is it will be k times q1.

01:03 X2 over r square times cosine of theta minus f2 is going to be k times q2 times q3 over r square i think what we can take is k times q3 let's call it r1 let's call it r2 k q3 is taken out so we are left with q1 q1 is two micropulum r1 is the distance between these two which is root 2 a so it's square will be 2a square cosine of theta will be adjacent over hypotenia so that's a over root 2a minus then we have a q2 uh q2 over here i think uh this will be q 1 so i made a mistake over here should have been 5 because we are left with q1 right so this is 5 and here we are left with q 2 and q 2 is 2 so that's going to be 2 times 10 raise 2 minus 6 over a square over here so that is the horizontal force towards the x -axis right k is 9 times 10 raised to 9 and q 3 is 5 so that's going to be 5 times 10 raised 2 minus 6 and this a and a is cancelled uh what i will lift over here is 5 over 2 .5 so that will be 2 .5 times 10 raised to minus 6 over a square minus 2 times 10 raised to minus 6 over a square over here.

02:42 So 9 times 5 is 45.

02:43 So that's 45 times 10 raised to 3...

Question

1. Consider three point charges located at the corners of a right triangle as shown in Fig., where q1=q3 = 5.00 ??, q2 = -2?C, and a= 0.100m. Find the resultant force exerted on q3.

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