00:01
A 7 micro 5 .5 capacitor that is initially in charge is connected in cgs with a 5 -oom resistor and amf of 50 volts, so it's like this.
00:10
This is 50.
00:11
This is the resistor.
00:12
This is the capacitor and this is all the circuit is.
00:14
And the instant when the electrical energy through the resistor is 300 watts, so what is the energy in the capacitor, okay? so if the power in the resistor is given as 300, and we know that the power is given by v square over r, so that is given to us as 300, right? so the value of v square will be 300 r, which means that v square will be 300 times 5.
00:41
So what will be the value of v? v as in the voltage across the resistor.
00:47
So at that instant, the voltage across the resistor will be root of 1500, which is coming as 38 .73 volts.
00:57
So if this is the voltage across resistor in that case, and definitely the total voltage drop should be 50 across the circuit because that's what the battery is supplying.
01:08
So the remaining should come across the capacitor, right? so the voltage across the capacitor will be the total emf minus the voltage across the resistor...