Question

Pseudocode FUNCTION NewtRaph ($x_0$, es, imax) i = 1 $x_i$ = $x_0$ ea$_i$ = 0 DO $x_{i+1}$ = $x_i$ - f($x_i$)/f'($x_i$) IF $x_{i+1}$ ? 0 THEN ea$_{i+1}$ = ABS(($x_{i+1}$ - $x_i$)/$x_{i+1}$) * 100 END IF DISPLAY i, $x_i$, f($x_i$), f'($x_i$), ea$_i$ IF ea$_i$ < es OR iter ? imax EXIT i = i + 1 END DO NewtRaph = $x_i$ END NewtRaph

          Pseudocode
FUNCTION NewtRaph ($x_0$, es, imax)
i = 1
$x_i$ = $x_0$
ea$_i$ = 0
DO
$x_{i+1}$ = $x_i$ - f($x_i$)/f'($x_i$)
IF $x_{i+1}$ ? 0 THEN
ea$_{i+1}$ = ABS(($x_{i+1}$ - $x_i$)/$x_{i+1}$) * 100
END IF
DISPLAY i, $x_i$, f($x_i$), f'($x_i$), ea$_i$
IF ea$_i$ < es OR iter ? imax EXIT
i = i + 1
END DO
NewtRaph = $x_i$
END NewtRaph

Pseudocode
FUNCTION NewtRaph (x0, es, imax)
i = 1
xi = x0
eai = 0
DO
xi+1 = xi - f(xi)/f'(xi)
IF xi+1 ? 0 THEN
eai+1 = ABS((xi+1 - xi)/xi+1) * 100
END IF
DISPLAY i, xi, f(xi), f'(xi), eai
IF eai < es OR iter ? imax EXIT
i = i + 1
END DO
NewtRaph = xi
END NewtRaph

Added by Luz J.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Patricia Holmes

Step 1

The function NewtRaph takes three parameters: X0 (initial guess), es (desired relative error), and imax (maximum number of iterations). Show more…

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Thanks for your feedback!

Pseudocode FUNCTION NewtRaph(X0, es, imax) i = 1 Xi = X0 eai = 0 DO xi+1 = Xi - (fx / fx') IF |Xi+1 - Xi| < es THEN eai+1 = |(Xi+1 - Xi) / Xi+1| * 100 END IF DISPLAY i, Xi, fx, fx', eai IF eai < es OR i > imax THEN EXIT END IF i = i + 1 END DO NewtRaph = Xi END FUNCTION