Convolution Theorem If f(t) and g(t) are piecewise continuous on [0, ?) and of exponential order, then ?{f * g} = ?{f(t)} ?{g(t)} = F(s)G(s).
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The Convolution Theorem states that if f(t) and g(t) are piecewise continuous functions on the interval [0, ∞), then the Laplace transform of their convolution, denoted as F(s) * G(s), is equal to the product of their individual Laplace transforms, denoted as F(s) Show more…
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