00:01
Hi, in this question we have a copper wire having radius r equals to 2 .70mm which can also be written as 2 .70 into 10 raised 2 power minus 3 meter.
00:15
Then we have density row which is equals to 8 .94 gram per centimeter cube which is equal to 8 .94 gram per centimeter cube which is equal to 8 .94 into 10 raised to par 3, kilogram per meter cube, then there is a current i which is equals to 6 .10 amp and the molar mass of copper, that is capital m, is given as 63 .5463 gram per mole, or we can write this as 63 .5463 into 10 raised 2 part minus 3 kilogram per mole.
01:10
So now we have to calculate the drift speed of the electrons in this copper wire.
01:16
So first of all we'll calculate the value for the area a of the copper wire which is equals to 5r square.
01:26
So we have the radius as 2 .70 into 10 raised to power minus 3.
01:31
So we'll just write this as 3 .14 into 2 .70 into 10 raised to power minus 3 whole square which will give the value of area equals to 22 .89 into 10 raised to power minus 6 meter square.
01:53
Now moving on next we'll calculate.
01:58
Value for electron density which is given as n and is equals to row n a divided by capital m where rose density n a is avogadro number and m is the molar mass of copper so we can calculate n equals to 8 .94 into 10 raise to power 3 into 6 .023 into 10 raise to power 23 divided by 0 .06354...