00:01
In this question, we are given with the differential equation y double dash plus y equals to e to the power minus a with the initial condition when x is 0, y is 0 and y dash is 0.
00:17
Now, the auxiliary equation of given differential equation is m square plus 1 equals to 0.
00:30
So, this implies m equals to plus minus iota.
00:36
The complementary solution will be yc equals to c1 cos t plus c2 sin t.
00:45
Let the particular solution yp is equals to a times of e to the power minus t.
00:52
So, y a dash p will be minus a e to the power minus t and y a double dash p will be equals to minus minus plus e to the power minus t.
01:05
T.
01:06
So, from here on substituting the values a e to the power minus t plus a e to the power minus t equals to e to the power minus t.
01:17
So, from here 2 a equals to 1.
01:21
So, a will be equals to 1 by 2.
01:23
So, therefore, the solution will be y equals to c1 cos c plus c2 sin t and plus 1 by 2 e to the power minus t...