\mathcal{L}\{\sin(t) + \cos(t)\} = ? \mathcal{L}\{e^{-2t}\} = ? \mathcal{L}\{te^{-2t}\} = ? \mathcal{L}^{-1}\left\{\frac{1\angle\pi/2}{s+1+j2} + \frac{1\angle-\pi/2}{s+1-j2}\right\} = ?
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C(sin(t) + cos(t)): To simplify this expression, we can use the trigonometric identity: sin(t) + cos(t) = sqrt(2) * sin(t + pi/4). Therefore, C(sin(t) + cos(t)) = C(sqrt(2) * sin(t + pi/4)). Show moreβ¦
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