A cube of ice, ? = 917 kg/m^3, is sliding down a...

A cube of ice, ? = 917 kg/m^3, is sliding down a frictionless incline that is 15° above level ground. Neglecting air resistance and any effects due to melting, determine the pressure the ice exerts on the incline, as it slides. The cube has a side length of 0.25 m. i. 1800 Pa ii. 2200 Pa iii. 3200 Pa iv. 6500 Pa v. There is not enough information to solve the problem. If the same cube of ice from problem (g) were allowed to float in a pool of fresh water, what height of ice would be above the surface of the water? Remember that the density of fresh water is ?_H2O = 1000 kg/m^3. i. 2.10 cm ii. 10.3 cm iii. 18.2 cm iv. 22.9 cm v. There is not enough information to solve the problem.

Transcript

00:01 Hello, a cube of ice with a density of 917 kilograms per cubic meter is sliding down on a frictionless incline which is at angle of 15 degrees.

00:18 The cube has a length of 0 .25 meters and we have to calculate the pressure which is exerting on the incline.

00:32 Let's illustrate this system.

00:37 So here the gravity is the gravity acting on the cube is directed downwards but the reaction of the floor is perpendicular to the incline.

00:50 That's why this n equals to m g times cosine alpha because this angle is alpha and then the pressure equals to m g times cosine and then the pressure equals to m g times cosine alpha divided by a squared on the other hand mass equals to density times a cube so therefore pressure equals to raw a g times cosine so that is 2 ,0 170 pascal which is roughly 2200 pascal therefore the answer is 2 .000 equation age.

02:14 The same cube floats in water and we have to calculate the height above the water surface.

02:26 So this height equals to the total volume of the cube minus volume in water and volume in water can be calculated as following.

02:39 So that equals to gravity acting on the cube divided by the the raw g where raw is stands for the density of water because here bion force balances gravity and the bian force equals to raw density of water times g times volume of cube in water so that is density of cube this volume is density of cube times a cube divided by density of water now and here when we calculate h, of course we have to multiply, divide it by one over.

03:26 We have to divide it by the area...

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