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d an equation for a rational function f(x) the Vertical asymptote at x=-2 and x=3 x-intercept s at (-10,0) and (-9,0) y-intercept at (0,180)

          d an equation for a rational function f(x) the Vertical asymptote at x=-2 and x=3 x-intercept s at (-10,0) and (-9,0) y-intercept at (0,180)
        

Added by Juan W.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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d an equation for a rational function f(x) the Vertical asymptote at x=-2 and x=3 x-intercept s at (-10,0) and (-9,0) y-intercept at (0,180)
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Transcript

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00:01 For this function, this rational, where we have x plus 2, x minus 3 in the numerator, just double checking, as well as x plus 5, x minus 1 in the denominator.
00:18 And to start with the first part, a, with the vertical asymptotes, i like to remind students that it's the non -cancelling factors in the denominator.
00:28 Denominator.
00:32 So non -cancelling and on bottom.
00:35 And you can set each piece equal to zero, although most of my students just haven't memorized that if it's a factor, the vertical asymptote would be the opposite.
00:47 So you subtract five over, same thing with x minus one.
00:50 The reason why you can just do the opposite, you have to do the inverse operation.
00:55 So there's part a, part b, the x intercept, well, the x intercept would be where y equals zero.
01:07 So that's a non -canceling in the numerator.
01:11 Oops, totally misspelled that.
01:18 Now, the reason why i talk about non -cancelling is if they cancel, it's actually not a vertical asymptote or an x intercept, it's actually what we consider it a whole.
01:28 So x plus 2 equal to 0 and x minus 3, but again, it's going to be the opposite because you subtract two over or you add three.
01:38 So that's part b.
01:40 Part c, as for the horizontal asthmpton.
01:43 This is a little bit trickier...
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