d) cosh 2x + sinh 2x = (e^(2x) + e^(-2x)) / 2 + (e^(2x) - e^(-2x)) / 2
Added by Darnell C.
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Now, let's look at the right side of the equation: = (e^2x + e^-2x) / 2 + (e^2x - e^2x) / 2 Simplifying this, we get: = (e^2x + e^-2x) / 2 = e^2x So, the right side of the equation also simplifies to e^2x. Show more…
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