d) ( frac{a^{3}-a b^{2}}{12} imes frac{16}{a b^{2}+b^{3}} )
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Step 1
The common factor in the numerator of the first fraction and the denominator of the second fraction is \(ab^2\). So, the expression becomes: \( \frac{a^{3}-a b^{2}}{12} \times \frac{16}{a b^{2}+b^{3}} = \frac{a^{3}}{12} \times \frac{16}{a + b} - \frac{a Show more…
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