(D^2 + 3D - 4)y = 15e^x
Added by Veronica G.
Step 1
The complementary equation is given by: (D^2 + 3D - 4)y_c = 0 This can be factored as: (D - 1)(D + 4)y_c = 0 The roots are r_1 = 1 and r_2 = -4. Therefore, the complementary solution is: y_c = C_1 e^x + C_2 e^{-4x} Show more…
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