00:01
Alright, so we have a stoichiometry question here.
00:02
It's just in a chart form to guide the calculations.
00:06
So we start with one molar copper sulfate and we have 100 milliliters of it and then we have 1 .39 grams of aluminum foil.
00:14
To get the moles of the copper sulfate, since we have the molarity in the volume, if we take 100 milliliters and then we multiply by one molar means that there's one mole in every 1000 milliliters, which is one liter.
00:30
So this is equal to 0 .1.
00:33
So there's 0 .1 moles of copper sulfate.
00:37
Then for aluminum, we have the grams.
00:41
So if we divide by the molar mass, which for aluminum is 26 .98 from the periodic table, then we can convert from grams to moles.
00:50
So 1 .39 divided by 26 .98 is 0 .0515.
01:08
Alright, then the moles of copper that we're going to get based on copper sulfate and then from aluminum.
01:17
So we can write the reaction.
01:21
So we have copper sulfate is reacting with aluminum.
01:25
Aluminum is more active, so it'll displace copper...