Question

\frac{d}{dx}[xe^x] = \newline \newline \circ e^x + \frac{x^2}{2}e^x \newline \circ e^x + ln(x)e^x \newline \circ e^x + xe^x \newline \circ e^x + x^2e^{x-1}

Name: (d)/(dx)[xe^x] = ∘e^x + (x^2)/(2)e^x ∘e^x + ln(x)e^x ∘e^x + xe^x ∘e^x + x^2e^x-1
Uploaded: 2023-05-23T10:51:02-08:00
Duration: 1 min 33 s
Channel: Madhur L
Description: (d)/(dx)[xe^x] = ∘e^x + (x^2)/(2)e^x ∘e^x + ln(x)e^x ∘e^x + xe^x ∘e^x + x^2e^x-1

          \frac{d}{dx}[xe^x] = \newline \newline \circ e^x + \frac{x^2}{2}e^x \newline \circ e^x + ln(x)e^x \newline \circ e^x + xe^x \newline \circ e^x + x^2e^{x-1}