00:01
Now we are given a function, i mean fx is equal to x plus absolute value of x to the power 2 plus 1.
00:09
We're required to compute f prime of 0.
00:14
Okay, for a very specific function like that to compute its derivative at some point, a very easy way for us to deal with those kind of things is to use just this definition.
00:26
I mean by the definition, they say it will be just equal to the limit as delta approaches 0, f0 plus delta x minus f0 and divided by delta x.
00:46
Okay, just plug as we have the expression of our f, we just need to plug all the 0, plug delta and f0 into our expression.
00:59
We get this is equal to f0 is 1, so f0 plus delta x, which is just equal to f delta x minus f0, which is 1 divided by delta x.
01:22
Okay, so this will be equal to limit as delta x approaches 0, delta x plus the absolute value of delta x to the power 2 divided by delta x.
01:38
Okay, let's just separate this exponential thing.
01:45
I mean, just use the square formula.
01:51
This is equal to, we have delta x to the power 2 and absolute value of delta x to the power 2 plus 2 times delta x times the absolute value of delta x.
02:08
We have the absolute value here divided by delta x.
02:12
Okay, now we can cancel the absolute value here because raising something to power 2 will always give us a non -active thing...