00:01
In this problem we are given that t is a linear transformation from the vector space rn to the vector space rm defined as t of v is equal to av where a is the matrix 1 to negative 1, 101.
00:21
The first question is to determine the dimensions of rn and rm.
00:30
Now if t is a linear transformation from a vector space rn to vector space rm and if a is the matrix corresponding to the linear transformation t, then a will be an m by n matrix where m is the dimension of rm, denoted as dimension of rm and n is the dimension of rn.
00:58
So here it is given that a is the metric corresponding to the linear transformation t from rn to rm and see that a is a 2 by 3 matrix and this means that dimension of rm is 2 and dimension of rn is 3.
01:29
Since a is a 2 by 3 matrix.
01:34
So these are the required first answers.
01:39
The second question is to determine the image under the linear transformation t of the vector v, which is the vector 522.
01:51
So we know that t of v is equal to av.
01:55
So that t of 522 will be the vector a which is the vector 1 to negative 1 1 1 .101 times the vector v which is the vector 522.
02:10
So perform this matrix multiplication.
02:14
We have this is the matrix 5 times 1 plus 2 times 2 plus negative 1 times 2 and the second row is 5.
02:25
5 times 1 plus 0 times 2 plus 1 times 2.
02:30
Therefore we get the image of the vector v is the vector 7 -7.
02:39
Therefore this is the required vector that will be the image vector...