Calculate the area of the segment cut from the curve $y = x(3 - x)$ by the line $y = x$. 2 sq. units 1 and 1/3 sq. units 3 sq. units 1 and 1/6 sq. units None of the Above
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Setting y = 0 in the equation of the curve, we get: 0 = 3 - x^2 Rearranging the equation, we have: x^2 = 3 Taking the square root of both sides, we get: x = ±√3 So, the curve intersects the x-axis at x = √3 and x = -√3. Show more…
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