Question

Demographics Suppose the number of citizens aged 45–64 years is approximated by: P(t) = 197.9 / (1 + 3.274e^(-0.0361t)) (0 ≤ t ≤ 25) where P(t) is measured in millions and t is measured in years, with t = 0 corresponding to the beginning of 1990. People belonging to this age group are the targets of insurance companies that want to sell them annuities. What is the expected population of citizens aged 45–64 years in 2010? In 2013? (Round your answers to one decimal place.) 2010: million people 2013: million people Demand for Computers A certain company found that the monthly demand for its new line of tablet computers t months after the line was placed on the market was given by: D(t) = 2500 - 1400e^(-0.03t) (t > 0) Graph this function and answer the following questions. (Round your answers to the nearest integer.) (a) What is the demand after 1 month? After 1 year? After 2 years? After 5 years? After 1 month: computers After 1 year: computers After 2 years: computers After 5 years: computers (b) At what level is the demand expected to stabilize? Computers (c) Find the rate of growth of the demand after the tenth month. Computers per month

          Demographics
Suppose the number of citizens aged 45–64 years is approximated by:

P(t) = 197.9 / (1 + 3.274e^(-0.0361t))

(0 ≤ t ≤ 25)

where P(t) is measured in millions and t is measured in years, with t = 0 corresponding to the beginning of 1990. People belonging to this age group are the targets of insurance companies that want to sell them annuities. What is the expected population of citizens aged 45–64 years in 2010? In 2013? (Round your answers to one decimal place.)

2010: million people
2013: million people

Demand for Computers
A certain company found that the monthly demand for its new line of tablet computers t months after the line was placed on the market was given by:

D(t) = 2500 - 1400e^(-0.03t) (t > 0)

Graph this function and answer the following questions. (Round your answers to the nearest integer.)

(a) What is the demand after 1 month? After 1 year? After 2 years? After 5 years?

After 1 month: computers
After 1 year: computers
After 2 years: computers
After 5 years: computers

(b) At what level is the demand expected to stabilize?

Computers

(c) Find the rate of growth of the demand after the tenth month.

Computers per month
        
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Added by Jacob G.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Demographics Suppose the number of citizens aged 45–64 years is approximated by: P(t) = 197.9 / (1 + 3.274e^(-0.0361t)) (0 ≤ t ≤ 25) where P(t) is measured in millions and t is measured in years, with t = 0 corresponding to the beginning of 1990. People belonging to this age group are the targets of insurance companies that want to sell them annuities. What is the expected population of citizens aged 45–64 years in 2010? In 2013? (Round your answers to one decimal place.) 2010: million people 2013: million people Demand for Computers A certain company found that the monthly demand for its new line of tablet computers t months after the line was placed on the market was given by: D(t) = 2500 - 1400e^(-0.03t) (t > 0) Graph this function and answer the following questions. (Round your answers to the nearest integer.) (a) What is the demand after 1 month? After 1 year? After 2 years? After 5 years? After 1 month: computers After 1 year: computers After 2 years: computers After 5 years: computers (b) At what level is the demand expected to stabilize? Computers (c) Find the rate of growth of the demand after the tenth month. Computers per month
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Transcript

-
00:01 So we have a demographics problem here.
00:02 We see that population is going to be given by 197 .91 plus 3 .274e to the negative 0 .0361t.
00:19 And we want to consider the expected population of citizens in 2010, where t equals zero corresponds to 1990.
00:30 So we want to know p of 20, and then we want to know 2013, so that's p of 23.
00:44 So let's consider what that is, if p of t is equal to 197 .91 plus 3 .274e to the negative 0 .0361t.
00:58 We plug this into our calculator with t equaling 20, we get 1 .9 .4, e to the negative 0 .0361t.
01:05 We plug this into our calculator.
01:05 99 .5 and that's in million people...
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