00:01
All right, so we have the following parametric equations in x and y, and we want the cartesian equation with respect to x and y.
00:09
So we know the following is true that based on trigonometric identities, sine squared of t plus cosine squared of t is equal to 1.
00:20
So let's solve for each of these in terms of sine and cosine.
00:23
So if we divide both of these by three, both sides, then we get, i'm just going to write it the other way so that we have it in terms of.
00:30
Of sine c.
00:31
So sine t is x over three.
00:34
So then if we want the sign squared, then we just square this.
00:38
So it's going to be x squared over three squared, which is nine.
00:42
All right.
00:43
So that's what we can plug in there.
00:45
And now for the cosine, so if we subtract four from both sides, we get y minus, well, let's just be consistent.
00:55
I'll just rearrange it...