Describe the x-values at which the function is differentiable. (Enter your answer using interval notation.) f(x) = (x + 5)^{2/3}
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The function will not be differentiable where the denominator is zero or where the function is not continuous. The denominator of the function is (x + 5)^(2/3). This will be zero when x = -5. So, the function is not differentiable at x = -5. Show more…
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